radiation with a wavelength of 640 nm appears as orange light to the human eye.

Question

radiation with a wavelength of 640 nm appears as orange light to the human eye. 1) Electromagnetie The frequency of this light iss-1, A) 4.688 x 1014 B) 4.688 x 10% C) 1.920 x 102 D) 1.920 x 1011 E) 2.133 x 10-15 transition results in the 2) Of the following transitions in the Bohr hydrogen atom, the emission of the highest-energy photon. d) n = 4 ? n-6 E) All transitions emit photons of equivalent energy 3) Calculate the energy (J) found in one photon of visible light if the wavelength is 589 nm. A) 3.37 x 1019 B) 1.17 x 1o3 C) 1.17 x 102 D) 3.37 x 10-28 E) 2.96 x 1018 4) Which one of the following represents an acceptable set of quantum numbers for an electron in an atom? (arranged as n, 1, m/, and ms) A) 3, 0, 0, -1/2 D) 0, 2, 1,0 E) 3, 3, 4, 3 5) Which of the following radiation sources from the electromagnetic spectrum has the shortest wavelength and greatest energy? A) radio B) microwave C) gamma D) visible E) ultraviole 6) At maximum, a d-subshell can hold A) 10 electrons. B) 6 C) 2 D) 8 E) 1 7) [Ar]4s23d104p3 is the electron configuration of a(n)atom. A) As C) P D) Sb E) S 8) The de Broglie wavelength of a particle is given by A) h+ mv B) hmv C) himv D) mvlc mv

Explanation / Answer

Ans 1

Wavelength = 640 nm x 10^-9 m/nm = 640*10^-9 m

Frequency = speed of light / wavelength

= (3*10^8 m/s) / (640*10^-9 m)

= 4.68 x 10^14 s-1

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