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I need to get the following Pseudocode to run in C++ // Pseudocode PLD Chapter 6

ID: 670465 • Letter: I

Question

I need to get the following Pseudocode to run in C++

// Pseudocode PLD Chapter 6 #2a & 2b, pg. 267

// Start

//     Declarations

//         num SIZE = 12

//         num numbers[SIZE]

//         num value = 0

//         num counter = 0

//         num total = 0

//         num average = 0

//         num diffFromAvg = 0

//         num SENTINEL = -1

//

//     output "Please enter a positive number: "

//     input value

//     while ((counter < SIZE) AND (value <> SENTINEL) )

//       total = total + value

//       numbers[counter] = value

//       counter = counter + 1

//       if (counter <> SIZE)

//         output "Please enter a positive number: "

//         input value

//       endif

//     endwhile

//

//     if (counter > 0) then

//       average = total/counter

//       for i = 0 to counter - 1

//         diffFromAvg = numbers[i] - average

//         output "Number[",i,"]: ",numbers[i]," Difference from Average is",diffFromAvg

//       endfor

//     else

//       output "Processing incomplete. No values in the array."

//     endif

// Stop

Explanation / Answer

#include<iostream>


using namespace std;
int main()
{
int SIZE=12;
int numbers[SIZE];
int value=0;
int counter=0;
int total=0;
int average=0;
int diffFromAvg=0;
int SENTINEL=-1;
cout<<"please enter a positive number: ";
cin>>value;
while((counter<SIZE)&&(value!=SENTINEL)){
total=total+value;
numbers[counter]=value;
counter++;
if(counter!=SIZE){
cout<<"please enter a positive number: ";
cin>>value;
}
}
if(counter>0){
average=total/counter;
cout<<average<<endl;
for(int i=0;i<counter;i++){
diffFromAvg=numbers[i]-average;
cout<<"Number["<<i<<"]: "<<numbers[i];
cout<<" Difference from Average is "<<diffFromAvg<<endl;
}
}
else{
cout<<"Processing incomplete.No values in the array"<<endl;
}


return 0;
}

here average is int

but convert to double to get decimal places and also replace the

average=sum/counter to average=(double)sum/(double)counter;