For each of these solutions, determine the osmotic pressure ofthe solution at ST

Question

For each of these solutions, determine the osmotic pressure ofthe solution at STP. (Assume these solutions behave ideally.) (a) 0.199 MFeCl2 in water
____________ atm

(b) 0.045 m CoCl2 inwater (Assume the density of the solution is 1.0 g/mL.)
_____________ atm

(c) 0.120 mol fraction glucose(C6H12O6) in water (Assume thedensity of the solution is 1.02 g/mL.)
____________ atm

(d) 0.0953 mol fraction NaCl in water(Assume the density of the solution is 1.00 g/mL.)
______________ atm
For each of these solutions, determine the osmotic pressure ofthe solution at STP. (Assume these solutions behave ideally.) (a) 0.199 MFeCl2 in water
____________ atm

(b) 0.045 m CoCl2 inwater (Assume the density of the solution is 1.0 g/mL.)
_____________ atm

(c) 0.120 mol fraction glucose(C6H12O6) in water (Assume thedensity of the solution is 1.02 g/mL.)
____________ atm

(d) 0.0953 mol fraction NaCl in water(Assume the density of the solution is 1.00 g/mL.)
______________ atm
(a) 0.199 MFeCl2 in water
____________ atm

(b) 0.045 m CoCl2 inwater (Assume the density of the solution is 1.0 g/mL.)
_____________ atm

(c) 0.120 mol fraction glucose(C6H12O6) in water (Assume thedensity of the solution is 1.02 g/mL.)
____________ atm

(d) 0.0953 mol fraction NaCl in water(Assume the density of the solution is 1.00 g/mL.)
______________ atm

Explanation / Answer

Osmotic pressure, = MRT                                R, gas constant = 0.0821 L- atm / K.mol STP stands for standard temperature and pressure, i.e 273 Kand 1 atm pressure So Absolute temperature, T = 273 K So = 0.199 M * 0.0821 L- atm / K.mol * 273 K         = 4.46atm

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