Sodium sulfite reacts with potassium iodate to produce the sulfateion, aqueous m

Question

Sodium sulfite reacts with potassium iodate to produce the sulfateion, aqueous molecular iodine and water. a) For this reaction identify the atoms that are oxidized andreduced, and specify the oxidizing and reducing agents. b) Write both the balanced oxidation and reductionhalf-reactions.
I don't even know where to start writing the chemicalequation!
a) For this reaction identify the atoms that are oxidized andreduced, and specify the oxidizing and reducing agents. b) Write both the balanced oxidation and reductionhalf-reactions.
I don't even know where to start writing the chemicalequation!

Explanation / Answer

a) Sulfite is converted to sulfate                                                    SO32- +1/2 O2 --------> SO42- Sulfur with a oxidation state of +4 is oxidized to+6.oxidation state Iodate is converted to iodine                         2 IO3-   -------->   I2 + 3O2 Iodine with a oxidation state of +5 is reduced to 0 oxidationstate Sulfur(sulfite) which is getting oxidized acts as reducingagent for the iodate group Iodine (Iodate) which is reduced acts as oxidizing agent forthe sulfite group. b) Oxidation:   SO32- + 1/2O2 --------> SO42- Reduction:  2 IO3-   -------->   I2 + 3O2 Sulfur with a oxidation state of +4 is oxidized to+6.oxidation state Iodate is converted to iodine                         2 IO3-   -------->   I2 + 3O2 Iodine with a oxidation state of +5 is reduced to 0 oxidationstate Sulfur(sulfite) which is getting oxidized acts as reducingagent for the iodate group Iodine (Iodate) which is reduced acts as oxidizing agent forthe sulfite group. b) Oxidation:   SO32- + 1/2O2 --------> SO42- Reduction:  2 IO3-   -------->   I2 + 3O2

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