Consider the reaction 2HCl(aq)+Ba(OH)2(aq)---->BaCl2+2H2O(l) H= -118kJ Calculate

Question

Consider the reaction 2HCl(aq)+Ba(OH)2(aq)---->BaCl2+2H2O(l) H= -118kJ
Calculate the heat when 100mL of 0.5M HCl is mixed with 300mL0.1M Ba(OH)2. Assuming that the temperature of both solutionswas initially 25 C and the final mixture has a mass of 400 g and aspecific heat capacity of 4.18 J/Cxg, calculate the finaltemperature of the mixture. show all steps please.
2HCl(aq)+Ba(OH)2(aq)---->BaCl2+2H2O(l) H= -118kJ
Calculate the heat when 100mL of 0.5M HCl is mixed with 300mL0.1M Ba(OH)2. Assuming that the temperature of both solutionswas initially 25 C and the final mixture has a mass of 400 g and aspecific heat capacity of 4.18 J/Cxg, calculate the finaltemperature of the mixture. show all steps please.

Explanation / Answer

From the reaction 2 mols of HCl reacts with 1 mol of Ba(OH)2 . No.of mols of HCl   = 0.1 L * 0.5 M                                =0.05 mols No.of mols of Ba(OH)2 = 0.3 L * 0.1M                                       =0.03 mols Formula :                 Heat evolved = s * m * T Given that  H= -118 kJ              Heat evolved = 118*1000J           mass ofsolution    = 400 g                             T    = T2 -T1                                      = T2 - 25 0C                  118*1000 J = 4.18 J/0C.g * 400 g * ( T2 -250C)              ( T2 -25 0C)    = 70.57                                 T2= 70.57 0C +25 0C                                      = 95.57 0C

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