Could you please explain how to do this equation step by step?Thanks so much!!!
ID: 677251 • Letter: C
Question
Could you please explain how to do this equation step by step?Thanks so much!!!A house with a 16.6 x 10^3 ft^2 floor area and 8.50ft high ceilingsis to be heated with propane. How many kilograms of propane wouldbe needed to raise the temperature of the air inside the house from65.0 degrees F to 73 degrees F? In this calculation you are ignoring the temperature of thewalls etc. The molar specific heat of the air inside the house is 30.2J/mole degrees C The average density of air over this temperature range can beestimated to be 1.22 g/L The molar mass of air is 29.1 g/mol There are 28.317 liters in a cubic foot The molar heat of combustion of propane is -2220.047KJ/mol
Could you please explain how to do this equation step by step?Thanks so much!!!
In this calculation you are ignoring the temperature of thewalls etc. The molar specific heat of the air inside the house is 30.2J/mole degrees C The average density of air over this temperature range can beestimated to be 1.22 g/L The molar mass of air is 29.1 g/mol There are 28.317 liters in a cubic foot The molar heat of combustion of propane is -2220.047KJ/mol
Explanation / Answer
Use the equation -H * n = c*M*T Where H is the molar heat of combustion of propane --2220.047 KJ/mol Where n is the moles for propane (C3H8) Where c is the molar specific heat of the air inside the house -30.2 J/moles degrees Celsius Where M is the moles of air (not mass) and T is the change intemperature inside the house (in Celsius) Find the volume of the house, which is the floor area * theceiling. You should get a number in cubic feet. Then covert your volume to liters by multiplying 28.317liters/cubic foot. Then find the mass of the air by multiplying the density (1.22 g/L)by the volume (liters). You should get the grams (which is a big number if you did itcorrectly). Multiply the grams of air by the molar mass given by 29.1 g/Mol andyou should get the moles of air. plug in the numbers to the equation above - -H * n = c *M*T (Remember it is -H because propane beingreleased to the house... -H = -(-2220.047 KJ/Mol). Alsoremember to covert your temperatures to Celsius. Once you find n (moles of propane), find the molar mass of propaneand multiply it by n, which you should get a number in grams.Convert grams into kilograms and you should get your answer.