For water, at its boiling point, the entropy of vaporizationis 118 J/K-mol. Assu

Question

For water, at its boiling point, the entropy of vaporizationis 118 J/K-mol. Assume a pressure of 1 atm.
Calculate the enthalpy of vaporization.
You need an equation that gives the unknown quantity in termsof the two given ones. Also entropy is usually reported in J/mol-k,while enthalpy usually reported in kJ/mole For water, at its boiling point, the entropy of vaporizationis 118 J/K-mol. Assume a pressure of 1 atm.
Calculate the enthalpy of vaporization.
You need an equation that gives the unknown quantity in termsof the two given ones. Also entropy is usually reported in J/mol-k,while enthalpy usually reported in kJ/mole

Explanation / Answer

Formula :    Svap   = Hvap / Tb                     Given data : Svap = 118 J/K-mol andTb = 373K (bioling temperature of water at 1 atm pressure)                    Hvap = Svap * Tb                                     =118 J.K-1mol-1 *373K                                     =44014J.mol-1                                     =44.014kJ.mol-1

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