2C4H6 ----> C8H12 was studied at 500 K and the followingdata were obtained Time

Question

2C4H6 ----> C8H12 was studied at 500 K and the followingdata were obtained
Time (s)    [C4H6] (mol/L) 195    1.6 x 10-2 604    1.5 x 10-2 1246    1.3 x 10-2 2180    1.1 x 10-2 6210    0.68 x 10-2
Assuming that    rate= -[C4H6]       t
determine the form of the rate law, integrated rate law, andthe rate constant for the reaction. (these are actualexperimental data, so they may not give a perfectly straight line). show all work please.
Time (s)    [C4H6] (mol/L) 195    1.6 x 10-2 604    1.5 x 10-2 1246    1.3 x 10-2 2180    1.1 x 10-2 6210    0.68 x 10-2
Assuming that    rate= -[C4H6]       t
determine the form of the rate law, integrated rate law, andthe rate constant for the reaction. (these are actualexperimental data, so they may not give a perfectly straight line). show all work please.

Explanation / Answer

We know that :         The given equationis :                  2C4H6----> C8H12           Byplotting the graph for the given values ;       We have to plot the graph ln[C4H6] vs time and other graphfor 1 / [C4H6] vs time        From the graph we caninterpret that        The plot   1 / [C4H6] vs time gives straight line which indicates thereaction is of second order.           Rate = - [C4H6] / t   = K[C4H6]2          Integrated rate law for the above Reaction is :            1/ [A]   = Kt + 1 / [A]0            The Rate constant for the above Reaction is :               K = Slope = (147.0- 6.25) x L/mole / (6210 - 195 ) sec                     = 0.0234 L / mole-s

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