Liquid methyl acetate reacts according to the balanced equation.When 7.99 mol of

Question

Liquid methyl acetate reacts according to the balanced equation.When 7.99 mol of CH3CO2CH3 isreacted, calculate the sign and magnitude (kJ) of the heatproduced.

2 CH3CO2CH3(l) + 7O2(g) 6 CO2(g) + 6H2O(l) .

the tolerance is +/-2%

Liquid methyl acetate reacts according to the balanced equation.When 7.99 mol of CH3CO2CH3 isreacted, calculate the sign and magnitude (kJ) of the heatproduced.

2 CH3CO2CH3(l) + 7O2(g) 6 CO2(g) + 6H2O(l) .

Enthalpy (kJ) H = -3189.9 Molar Mass CH3CO2CH3 74.080 O2 31.999 CO2 44.001 H2O 18.015

Explanation / Answer

We Know that :       The given reaction is :            2CH3CO2CH3(l) + 7O2(g) 6 CO2(g) + 6H2O(l) .           numberof moles of methyl acetate = 8.0 moles            Hrxn. = Hproducts   - Hreactants                         = 24 x (- 393.5 KJ ) + 24 x (-285.83 KJ)   - [ 8.0 x (-431.4 KJ ) + 28 x(0 KJ) ]                         = - 12852.72 KJ   So the heat produced isNegative i.e Exothermic Reaction.                         = 24 x (- 393.5 KJ ) + 24 x (-285.83 KJ)   - [ 8.0 x (-431.4 KJ ) + 28 x(0 KJ) ]                         = - 12852.72 KJ   So the heat produced isNegative i.e Exothermic Reaction.

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