6 H 3 BO 3 ---> H 4 B 6 O 11 + 7 H 2 O Using the balanced equations from the rea

Question

6 H3BO3   --->  H4B6O11   +   7 H2O    Using the balanced equations from the reactionsabove,

 determine the following:

If I have 2 moles ofH3BO3 , how many gramsof H4B6O11 willform? 6 H3BO3   --->  H4B6O11   +   7 H2O    Using the balanced equations from the reactionsabove,

 determine the following:

If I have 2 moles ofH3BO3 , how many gramsof H4B6O11 willform?    Using the balanced equations from the reactionsabove,

 determine the following:

If I have 2 moles ofH3BO3 , how many gramsof H4B6O11 willform?

Explanation / Answer

                   6H3BO3   --->  H4B6O11   +   7 H2O         molar mass of H4B6O11   is = 4*1+6*10.81 + 11*16.0 g/mol                                                      =244.86 g/mol           6 molesof H3BO3 reacted to form 244.86 g of  H4B6O11 .          2moles of H3BO3 forms (2 * 244.86 / 6 ) = 81.62 gof    H4B6O11

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