Place the following compounds in order from the highest to the lowestoxidation n

Question

Place the following compounds in order from the highest to the lowestoxidation number for carbon.
1 C6H12O6
CO2
CH3OH
CH4
C6H6

> 2 C6H12O6
CO2
CH3OH
CH4
C6H6

> 3 C6H12O6
CO2
CH3OH
CH4
C6H6

> 4 C6H12O6
CO2
CH3OH
CH4
C6H6

> 5 C6H12O6
CO2
CH3OH
CH4
C6H6


Place the following compounds in order from the highest to the lowestoxidation number for carbon.
1 C6H12O6
CO2
CH3OH
CH4
C6H6
1 C6H12O6
CO2
CH3OH
CH4
C6H6
1 2 C6H12O6
CO2
CH3OH
CH4
C6H6
2 C6H12O6
CO2
CH3OH
CH4
C6H6
2 3 C6H12O6
CO2
CH3OH
CH4
C6H6
3 C6H12O6
CO2
CH3OH
CH4
C6H6
3 4 C6H12O6
CO2
CH3OH
CH4
C6H6
4 C6H12O6
CO2
CH3OH
CH4
C6H6
4 5 C6H12O6
CO2
CH3OH
CH4
C6H6
5 C6H12O6
CO2
CH3OH
CH4
C6H6
5
1 C6H12O6
CO2
CH3OH
CH4
C6H6

> 2 C6H12O6
CO2
CH3OH
CH4
C6H6

> 3 C6H12O6
CO2
CH3OH
CH4
C6H6

> 4 C6H12O6
CO2
CH3OH
CH4
C6H6

> 5 C6H12O6
CO2
CH3OH
CH4
C6H6

Explanation / Answer

We Know that :     The Oxidation state of Carbon in the givencompounds can be calculated as :        C6H12O6          6 ( C ) + 12( +1 ) + 6 ( -2 ) = 0           6 ( C) + 12 - 12 = 0                  C = 0        CO2         C + 2 ( - 2 ) = 0           C = +4                 CH3OH          C + 3 ( +1) -2 +1 = 0           C = - 2                      CH4             C + 4 ( +1 ) = 0                C =   -4                           C6H6             6 x C + 6 ( +1 ) = 0               C = - 1           The arrangement of carbon atoms with respect to theincrease in the Oxidation states can be written as :              CO2 > C6H12O6 > C6H6 > CH3OH > CH4             C + 4 ( +1 ) = 0                C =   -4                           C6H6             6 x C + 6 ( +1 ) = 0               C = - 1           The arrangement of carbon atoms with respect to theincrease in the Oxidation states can be written as :              CO2 > C6H12O6 > C6H6 > CH3OH > CH4

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