A volatile liquid produced 0.339 g of vapor in a 225.0 mLflask at 1000C and 1.00

Question

A volatile liquid produced 0.339 g of vapor in a 225.0 mLflask at 1000C and 1.00 atm. What is the molar mass of theliquid? a. 89.4 g/mol b. 56.4 g/mol c. 46.1 g/mol d. 12.4 g/mol e. Not enough information is given. answer C, explain why?
Magnesium metal reacts with hydrochloric acid to form aqueousmagnesium chloride and hydrogen gas. An excess of magnesium isreacted with 6.00 x 10-2 moles of hydrochloric acid and all of thehydrogen is collected in a balloon at 250C and 1.00 atm. What isthe expected volume of the balloon? a. 0.672 L b. 0.734 L c. 1.34 L d. 1.47 L e. 22.4 L Answer B, explain why? A volatile liquid produced 0.339 g of vapor in a 225.0 mLflask at 1000C and 1.00 atm. What is the molar mass of theliquid? a. 89.4 g/mol b. 56.4 g/mol c. 46.1 g/mol d. 12.4 g/mol e. Not enough information is given. answer C, explain why?
Magnesium metal reacts with hydrochloric acid to form aqueousmagnesium chloride and hydrogen gas. An excess of magnesium isreacted with 6.00 x 10-2 moles of hydrochloric acid and all of thehydrogen is collected in a balloon at 250C and 1.00 atm. What isthe expected volume of the balloon? a. 0.672 L b. 0.734 L c. 1.34 L d. 1.47 L e. 22.4 L Answer B, explain why? Magnesium metal reacts with hydrochloric acid to form aqueousmagnesium chloride and hydrogen gas. An excess of magnesium isreacted with 6.00 x 10-2 moles of hydrochloric acid and all of thehydrogen is collected in a balloon at 250C and 1.00 atm. What isthe expected volume of the balloon? a. 0.672 L b. 0.734 L c. 1.34 L d. 1.47 L e. 22.4 L Answer B, explain why?

Explanation / Answer

We Know that :     According to ideal gas equation :          PV =nRT           1 atmx 225.0 / 1000 L = 0.339 g / M x 0.0821 atm-L / mol-K x 373 K            Molecular weight of the gas =  46.13910533 g / mole           Mg(s) + 2 HCl   --------> MgCl2 + H2          According to ideal gas equation :             PV = nRT              1.0 atm x V = 3 x 10-2 mol x 0.0821atm-L / mol -K x 298 K                     V = 0.734 L           Mg(s) + 2 HCl   --------> MgCl2 + H2          According to ideal gas equation :             PV = nRT              1.0 atm x V = 3 x 10-2 mol x 0.0821atm-L / mol -K x 298 K                     V = 0.734 L      

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