Choose the cell notation that corresponds to anelectrochemical cell that has the

Question

Choose the cell notation that corresponds to anelectrochemical cell that has the electrode reactions shown.

2H+(aq) + 2e- H2(g)
H2SO3(aq) + H2O(l) SO42-(aq) + 4H+(aq) +2e-

Pt(s) l H+(aq) l H2(g) llH2SO3(aq), SO42-(aq),H+(aq) l Pt(s) Pt(s) l H2SO3(aq),SO42-(aq), H+(aq) llH+(aq) l H2(g), Pt(s) Pt(s) l H2SO3(aq),SO42-(aq), H+(aq) llH+(aq), H2(g) l Pt(s) Pt(s) l H2SO3(aq),SO42-(aq) ll H2(g) l Pt(s)
St. Red. Pot. (V) SO42-/H2SO3 +0.20 H+/H2 0 Choose the cell notation that corresponds to anelectrochemical cell that has the electrode reactions shown.

2H+(aq) + 2e- H2(g)
H2SO3(aq) + H2O(l) SO42-(aq) + 4H+(aq) +2e-

Pt(s) l H+(aq) l H2(g) llH2SO3(aq), SO42-(aq),H+(aq) l Pt(s) Pt(s) l H2SO3(aq),SO42-(aq), H+(aq) llH+(aq) l H2(g), Pt(s) Pt(s) l H2SO3(aq),SO42-(aq), H+(aq) llH+(aq), H2(g) l Pt(s) Pt(s) l H2SO3(aq),SO42-(aq) ll H2(g) l Pt(s)
St. Red. Pot. (V) SO42-/H2SO3 +0.20 H+/H2 0

Explanation / Answer

In cell representation, left hand half cell isoxidation half cell (where oxidation takes place) and righthand half cell reduction half cell (whetre reduction takesplace)    Pt(s)|H2SO3(aq),SO42-(aq),H+(aq)||H+(aq), H2(g)|Pt(s)   is the correct representation among thegiven options. Second option is is very close to the correct optionbut it is principally wrong because the single verticle bar onright hand half cell must be in between H2(g) , Pt(s) , whichrepreasents seperation between electrode and electrolyte.

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