can someone please help me with the following problem.pleaseand thank you! The h

Question

can someone please help me with the following problem.pleaseand thank you!
The heat of fusion of water is 80 cal/g, the heat of vaporizationof water is 540 cal/g, the specifc heat of ice is 0.48 cal/deg/g,the specific heat of steam is 0.48 cal/deg/g and the specific heatof liquid water is 1.0 cal/deg/g. How much heat would be needed toconvert 12.35 g of ice at -23 °C to steam at 114 °C?

can someone please help me with the following problem.pleaseand thank you!
The heat of fusion of water is 80 cal/g, the heat of vaporizationof water is 540 cal/g, the specifc heat of ice is 0.48 cal/deg/g,the specific heat of steam is 0.48 cal/deg/g and the specific heatof liquid water is 1.0 cal/deg/g. How much heat would be needed toconvert 12.35 g of ice at -23 °C to steam at 114 °C?

Explanation / Answer

Q = cmT Q = Lm Q = (0.48 cal/deg/g)(12.35 g)(23 deg) Q = (80 cal/g)(12.35) Q= (1.0 cal/deg/g)(12.35 g)(100) Q = (540 cal/g)(12.35 g) Q = (0.48 cal/deg/g)(12.35 g)(14 deg) Q total = 9111.336 calof heat here is a nice diagram that may help you understandhttp://hyperphysics.phy-astr.gsu.edu/hbase/thermo/phase.html

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