Why is there suppose to be 2 Cl and 2 Ag, in the final equation, Ihave them mark

Question

Why is there suppose to be 2 Cl and 2 Ag, in the final equation, Ihave them marked in red...

The total question is here in Green...
Write a balanced net ionic equation for thereduction of UO2+2 in a WaldenReductor...
What was done, was just taken the standard Walden reductor...
Ag + Cl ---> AgCl

and the UO_2 equation...

UO2+2 + 4H + 2e- ---> U4+ + 2H2O

Combined the two together... and go the same thing, except withoutthe 2's in front of the Ag and Cl, and I can't figure out why theywould be there. The equation is balanced with just 1 Ag and 1 Cl,so why bother adding another 2 in there?

The answer is suppose to be UO2+2+ 4H+ + 2Cl- +2 Ag+ ----> U4+ +H2O + 2 AgCl

Thanks for any help and like always I rate...

Explanation / Answer

I noticed that you don't have the 2 in front of the AgClmarked in red. You need the 2's in front of the Ag and Cl tobalance out AgCl. If that is not your problem this could be it.... You have to multiply by two because of the electrontransfer. In Ag + Cl -> AgCl only one electron is transferred. In theUO_2 equation there are two electrons being transferred. Hope this helps!

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---