The equilibrium constatnt Kc for the reaction A (g)+B(g) C (g) is 0.75 at 150 degree C. If 0.800 mol of Ais added to 0.600 mol of B in a 1.00 L container at 150 degree C,what will be the equilibrium concentration of C. a. 0.19M b. 0.36M c. 0.41M d.0.61M Please show work. Thanks The equilibrium constatnt Kc for the reaction A (g)+B(g) C (g) is 0.75 at 150 degree C. If 0.800 mol of Ais added to 0.600 mol of B in a 1.00 L container at 150 degree C,what will be the equilibrium concentration of C. a. 0.19M b. 0.36M c. 0.41M d.0.61M Please show work. Thanks
Explanation / Answer
A (g) + B (g) C(g) I(M) 0.8 0.6 0 C(M) -x -x +x E(M) 0.8 - x 0.6 -x +x K = (x) / ( 0.8 -x )(0.6 - x ) x - 0.75 ( 0.8- x )(0.6- x ) = 0 On solving the above equation we get x = 0.188 M =[ C] So it could be rounded of f to get 0.19 M . Option ais the answer.