Can someone please help me? 1.If you mix 125 mL of a buffer at pH 9.32 with 125
ID: 683162 • Letter: C
Question
Can someone please help me? 1.If you mix 125 mL of a buffer at pH 9.32 with 125 mL of purewater, what will be the pH of the resulting solution?2.When the mole ratio of conjugate base to its conjugate acidis 1 to 1, the pH of the solution will be ________
Can someone please help me? 1.If you mix 125 mL of a buffer at pH 9.32 with 125 mL of purewater, what will be the pH of the resulting solution?
2.When the mole ratio of conjugate base to its conjugate acidis 1 to 1, the pH of the solution will be ________
Explanation / Answer
1. The pH will remain 9.32 as the ratio of the base to acid formhas not changed. Dilutinga buffer does NOT change its pH just itsbuffer capacity ( how much acid or base it can react with beforethe pH changes by 1 pH unit.) 2. When the molar ratios of the base to the acid forms in a bufferare equal then , the pH = pKa of the weak acid H/H : pH = Pka + log [base]/[acid]:::::: if the two forms haveequal concentration then base/acid = 1 :::::: pH = pKa + log 1 log 1 = 0::::: soo :::::::::: pH = pKa