Use the data in this table to calculate the solubility of each sparinglysoluble

Question

Use the data in this table to calculate the solubility of each sparinglysoluble substance in its respective solution. (a) magnesium carbonate in 6.3*10-3 MNa2CO3(aq)
(b) nickel(II) hydroxide in 0.222M NiSO4(aq); For the purpose of thiscalculation, ignore the autoprotolysis of water.
Use the data in this table to calculate the solubility of each sparinglysoluble substance in its respective solution. (a) magnesium carbonate in 6.3*10-3 MNa2CO3(aq)
(b) nickel(II) hydroxide in 0.222M NiSO4(aq); For the purpose of thiscalculation, ignore the autoprotolysis of water.

Explanation / Answer

We Know that :        MgCO3 <--------> Mg+2 + CO3-2                                          S           S + 6.3x 10-3                    Ksp = S ( S + 6.3x 10-3 )              2.0 x 10-5 = S ( S + 6.3 x 10-3)           Solvingthe above equation we get :               S = 0.00232 M     b.             Ni (OH)2 <---------> Ni+2 + 2 OH-                                                  S + 0.222   2 S              Ksp =  ( S + 0.222 ) (2S) 2           5.48 x 10-16   = 4S2 (S + 0.222 )             Solving the above equation we get :                S = 2.484 x 10-8 M                                                  S + 0.222   2 S              Ksp =  ( S + 0.222 ) (2S) 2           5.48 x 10-16   = 4S2 (S + 0.222 )             Solving the above equation we get :                S = 2.484 x 10-8 M           5.48 x 10-16   = 4S2 (S + 0.222 )             Solving the above equation we get :                S = 2.484 x 10-8 M

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