Ka (HNO3) = [H3O][NO3] / [HNO3] = 20 Ka (NH4) = [H3O][NH3] / [NH4] = 5.6E-16 Ok

Question

Ka (HNO3) = [H3O][NO3] / [HNO3] = 20
Ka (NH4) = [H3O][NH3] / [NH4] = 5.6E-16
Ok my question is where do they get the values of the productsand reactants to get these answers. I looked in my book where theionization constants are, but didn't find anything. Am I notlooking in the right place? Thank you. Need this so I can go to sleep.
Ka (NH4) = [H3O][NH3] / [NH4] = 5.6E-16
Ok my question is where do they get the values of the productsand reactants to get these answers. I looked in my book where theionization constants are, but didn't find anything. Am I notlooking in the right place? Thank you. Need this so I can go to sleep.

Explanation / Answer

We Know that :         HNO3(aq) + H2O ---------> H3O+ (aq) + NO3-(aq)          Ka = [H3O+] [NO3-]/ [HNO3] at standard temperature Ka = 2.4 x 101       NH4+ (aq) + H2O ---------> NH3 (aq)+ H3O+ (aq)          Ka = [H3O+] [NH3] / [NH4+] at standard temperature Ka =  5.52 x 10-10   [ Kb of NH3 1.81 x 10^-5                                                                                                                        Ka = Kw / Kb = 5.52 x10-10   ]       NH4+ (aq) + H2O ---------> NH3 (aq)+ H3O+ (aq)          Ka = [H3O+] [NH3] / [NH4+] at standard temperature Ka =  5.52 x 10-10   [ Kb of NH3 1.81 x 10^-5                                                                                                                        Ka = Kw / Kb = 5.52 x10-10   ]

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