ammonia gas can be prepared by the reaction of a metal oxide suchas calcium oxid

Question

ammonia gas can be prepared by the reaction of a metal oxide suchas calcium oxide with ammonium chloride.

CaO(s) + NH4Cl(s) --->NH3(g) + H2O(g) +CaCl2(s)

CaO,MW=56.08            NH3,MW= 17.03   CaCl2,MW=110.98
NH4Cl,MW=53.49         H2O,MW=18.02

a. Calculate the mass of NH3 that is formed when 24.3gof CaO is reacted with 48.6g of NH4Cl.

b. Which reactant is the limiting reactant?

Explanation / Answer

CaO(s) +2NH4Cl(s) --->2NH3(g) +H2O(g) +CaCl2(s) 56.08g      106.98g          34.06g      18.02 g    110.98g 56.08g CaO reacts with 106.98g NH4Cl So 24.3g CaO reacts with 46.36g NH4Cl Hence CaO is the limiting reactant. 56.08g CaO gives 34.06g NH3 24.3g CaO gives 14.76g NH3

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