Goal:HCl(g)+NaNO 2 (s)-->HNO 2 (l)+NaCl(s) 1.2NaCl(s)+H 2 O(l)-->2HCl(g)+Na 2 O(

Question

Goal:HCl(g)+NaNO2(s)-->HNO2(l)+NaCl(s) 1.2NaCl(s)+H2O(l)-->2HCl(g)+Na2O(s)               +507.31kJ 2.NO(g)+NO2(g)+Na2O(s)--->2NaNO2(s)           -427.14kJ 3.NO(g)+NO2(g)--->N2O(g)+O2 (g)                           -42.68kJ 4.2HNO2(l)--->N2O(g)+O2(g)+H2O(l)                  +34.45kJ Goal:HCl(g)+NaNO2(s)-->HNO2(l)+NaCl(s) 1.2NaCl(s)+H2O(l)-->2HCl(g)+Na2O(s)               +507.31kJ 2.NO(g)+NO2(g)+Na2O(s)--->2NaNO2(s)           -427.14kJ 3.NO(g)+NO2(g)--->N2O(g)+O2 (g)                           -42.68kJ 4.2HNO2(l)--->N2O(g)+O2(g)+H2O(l)                  +34.45kJ

Explanation / Answer

2NaCl(s)+H2O(l)-->2HCl(g)+Na2O(s)              :H 1 = +507.31kJ   ---(1) NO(g)+NO2(g)+Na2O(s)--->2NaNO2(s)          :H 2 =  -427.14kJ   --(2) NO(g)+NO2(g)--->N2O(g)+O2 (g)                           :H 3 = -42.68kJ   ----(3) 2HNO2(l)--->N2O(g)+O2(g)+H2O(l)                 :H 4 =  +34.45kJ   ----(4) HCl(g)+NaNO2(s)-->HNO2(l)+NaCl(s) :   H = ?   ---(5) Eq(5) can be obtained by the following sequence Eq(5) = (1/2 ) * { revarse Eq(1) + reverse Eq(2) + Eq(3) +reverse Eq(4) } H = ( 1/2) * { -H 1 - H2 + H3 - H 4 }       = - 78.65 KJ

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