Calculate the acetate ion concentration in a solution prepared by dissolving 9.1

Question

Calculate the acetate ion concentration in a solution prepared by dissolving 9.10 times 10 - 3 mol of HCl(g) in 1.00 L of 1.20 M aqueous acetic acid (Ka = 1.80 times 10 - 5). Assume that the volume of the solution does not change upon dissolution of the HC1. Calculate the pH of the above solution. Give your answer to two decimal places.

Explanation / Answer

HCl + CH3COOH ---> CH3COOCl + H2O Ka = product/ reactant 1.8 x 10^-5 = [CH3COOCl][H2O] / [HCl][CH3COOH] 1.8 x 10^-5 = [CH3COOCl][1] / [9.1 x 10^-3 M][1.20M] CH3COOCl = 1.97x10^-7 pH = -log CH3COOCl pH = 6.71

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---