2 SO 2 (g) + O 2 (g) <---> 2SO 3 (g) Initial pressure (atm) 0.65 0.84 0.54 Chang

Question

2 SO2(g) + O2(g) <---> 2SO3(g) Initial pressure (atm)   0.65    0.84   0.54 Change in pressure (atm) Equilibrium pressure (atm)    Y      Z   0.34
When the table is completed, the equilibrium pressure forSO2, labeled Y, is ? What is the value for Kp for the abovereaction?
Initial pressure (atm)   0.65    0.84   0.54 Change in pressure (atm) Equilibrium pressure (atm)    Y      Z   0.34
When the table is completed, the equilibrium pressure forSO2, labeled Y, is ? What is the value for Kp for the abovereaction?

Explanation / Answer

For the given reaction,                         2 SO2(g) + O2(g) <---> 2SO3(g)              I(atm)   0.65         0.84              0.54              C          -2x            -x                 +2x                EQ       y              z                   0.34 We observe that the final pressure of productsdecreased, thus we conclude that the equillibrium shifts toleft. Threfore -             0.54 + 2x = 0.34 -------> x = - 0.1atm Therefore            PSO2 = 0.65-2(-0.1) = 0.85 atm                             PO2 = 0.84 + 0.1 = 0.94 atm Therefore              Kp = PSO32 / PSO22 * PO2                                      = (0.34)2 / (0.85)2 * (0.94)                                      = 0.170                                      = (0.34)2 / (0.85)2 * (0.94)                                      = 0.170

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