The capacity of an irregularly shaped vessel cannot be computedfrom geometric da

Question

The capacity of an irregularly shaped vessel cannot be computedfrom geometric data. As a result, it is decided that the volume beestablished from analytical data. The vessel is filled to itscapacity mark with chloride-free water. A known amount of sodiumchloride is introduced, and a homogeneous solution obtained bystirring. A measured portion of the solution is withdrawn andtitrated with silver nitrate.

In the experiment, 1.32 kg of NaCl (58.44 g/mol) were dissolved inthe vessel. A 0.500 liter portion of the solution was removed fromthe vessel and a Mohr titration for chloride was performed. What isthe capacity of the vessel in liters if 46.50 mL of 0.502 MAgNO3 were required to reach the endpoint?

The answer should be: 484 L, but I need to understand how to solveit. Thanks.

Explanation / Answer

NaCl (aq) + AgNO3 (aq) ..............> AgCl (s)+ NaNO3 (aq) At equivlence point, moles of Cl- (aq) = moles ofAg+ (aq)                                                               0.500L * C   = 46.50mL * 0.502M                               0.500L * C   = 0.04650L * 0.502M                                 C = 0.0467M Moles of NaCl = 1.32kg / (58.44g/mol)                         = 1320g / (58.44g/mol)                         = 22.59mol Volume of vessel = 22.59mol / (0.0467M)                             =22.59mol / (0.0467 mol /L)                            = 483.73L                            = 484L    (approximatley)

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