1. A metal that weighs 5.75g is 50.0degrees Celsius. When placed into calorimete

Question

1.     A metal that weighs 5.75g is 50.0degrees Celsius. When placed into calorimeter with 25.00mL of waterat 23.0 degrees Celsius the temperature of rose to 27.0 degreesCelsius. the specific temperature of the water is 4.184J/K-g. What is the specific heat of the metal?

2.     If a gas occupies 250.0ml at STP,what volume will it occupy at a pressure of 700.0mm HG and at atemperature of 25.0 degrees Celsius?

3.     A gas collected over water at 25.0degrees Celsius. Vapor pressure of water at25.0 degrees Celsius isequal to 23.8mmHg. The atmospheric pressure is 745.ommHg. What isthe pressure of the gas?

Explanation / Answer

1.   Heat lost gy the metal = Heat gained by thewater                              mcdt = m'c'dt' 5.75g * c * ( 50 - 27)K = ( Volume * density ) * 4.184J / K - g * ( 27 - 23 )K                                        = ( 25 mL * 1 ) * 4.184 * 4                                     c = 3.1637 J / K -g 2. We lnow PV = nRT So for a given of two cases PV / T = P'V' / T'      760 mm Hg * 250 mL / 273 K= 700 mm Hg * V' / (25+273)                                                V' = 296.285 mL 3. Total pressure , P = Sum of the partial pressures                             P= p ' + p ''               745 m Hg = 23.8 mm Hg + p ''                         p '' = 721.2 mm Hg

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