Consider the following statements and determine which are true andwhich are fals

Question

Consider the following statements and determine which are true andwhich are false.
KrF4 is a polar molecule.
Bond angles for IF6+ are 60 °.
NO3- has only two resonance Lewisstructures.
KrF4 has a tetrahedral structure.
The formal oxidation state of an atom in a molecule(or molecular ion) can be calculated as:
(the number of valence electrons on a free atom)minus (half the number of electrons in bonds to that atom)minus (the number of unshared electrons assigned to theatom in the molecule)
SeF4 is a polar molecule.

Explanation / Answer

KrF4 is a polar molecule. (TRUE) No . of hybrid orbitals , H = (V + S - C + A ) / 2 Where V = Valence of the central atom = 8 S = No . of single valence atoms = 4 C = No . of cations = 0 A = No .of anions = 0 H =( 8 + 4 -) + 0 ) / 2    = 6                     ---- corresponding to sp3d2  ybridization So , the expected structure is octahedral . But outof the 8 valence electrons, 4 are occupied by the tfour Fatoms & 2 lone pairs of electrons is remained as non bonded, soits structure is square planar. Bond angles for IF6+ are 60 ° ( false )
H = ( 7 + 6 -1 + 0 ) / 2     =6                     ----corresponding to sp3d2  ybridization So , the expected structure is octahedral . So thebond angle is 90 o NO3- has only two resonance Lewisstructures ( False), It has three resonnce forms KrF4 has a tetrahedral structure. ( False ) It hassquare planar structure Formal Charge = the number of valence electrons on a freeatom) minus (half the number of electrons in bonds to thatatom) minus (the number of unshared electrons assigned tothe atom in the molecule ( TRUE) Formal Charge = No. of valence electrons - (allunshared electrons + ½ of the shared electrons) SeF4 is a polar molecule( TRUE) SeF4 is a polar molecule( TRUE)

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