Show Timer Question Completion Status Question 5 3 points Match each reaction wi

Question

Show Timer Question Completion Status Question 5 3 points Match each reaction with the correct classification B NaOH (aq) + HCIO4(aq) NaCIO4(aq) + H2O(1) Bc2H4 (g) + 3O2(g) 2CO2 (g) + 2H20 (I) A acid-base " C precipitation Question 6 1 points Sa What is the formula of the salt that forms from the following acid-base reaction? HNO3 (aa) + Ba(OH)2 (aa)- BaNO3 Ba(NO3)2 2 points Sav Question 7 Consider the following reaction: 8SO2 + 16H25 3S8 + 16H20 What is the maximum mass of Sg that can be produced by combining 90.0 g of each reactant? What is the limiting reactant? (Input answer as S02 or H25) 2 pointsSave A Question 8 A chemical reaction can theoretically yield 246 g of product. If a laboratory experiment vields 102 g of product, what is tue pere 5 8

Explanation / Answer

5)

NaOH (aq) + HClO4 (aq)   this is Acid-base reaction

C2H4 (g) + 3O2 (g) :       this is Oxidation - Reduction

(NH4)3PO4 + AlCl3 :      this is   Pecipitation reaction

6) 2HNO3 + Ba(OH)2         --------------> Ba(NO3)2 + 2H2O

salt formed is Ba(NO3)2

7)    8 SO2 + 16 H2S ----------> 3 S8 + 16 H2O

      mol Wt of SO2 = 64 g

      MOl wt of H2S = 34 g

    512 g (8 * 64 g) SO2 requires 544 g (16 * 34 g) H2S

    90 g of SO2 required 90 * 544 / 512 = 95.625 g H2S

   but we have only 90 g of H2S with . So limiting rectant is H2S

   calculating the amount of S8 with respect to the H2S

   544 g H2S gives 3*(32*8) g S8 = 768 g S8

90 g H2S gives (90 * 768) / 544 = 127.05 g S8

Took some effort to answer all the question :)

     

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---