Consider an element, A, that has two isotopes, x and y. If the natural abundance
ID: 694606 • Letter: C
Question
Consider an element, A, that has two isotopes, x and y. If the natural abundances of each isotope are a b (a + b = 1), respectively, and there are two atoms of the element in a molecule, the probability of finding anu each combination of isotopes can be determined by the following equations: probability of two A atoms a probability of one "A atom and oe 'A atom 2ab probability of two 'A atoms-b Using the equations above and the information provided in the table, calculate the probablity of finding each isotope combination of Br in CBr2Fz Element Mass Mass (Da) Abundance Number (atom %) 1 Probability of finding two 79er atoms. H 11.007825 99.988 - Number 2.01410 0.012 10.01294 199 10 11 11.00931 80.1 0 16 15 999491 99 757 Probability of finding one "Br atom and one "Br atom 17 16.99913 0.038 18 19 35 37 17.99916 0.205 18.99840 100 34.96885 75.78 Number Scroll down for another question. Cl 36.96590 24 22 78.91834 50.69 Br 79 Probability of finding two 8'Rr atnms Hint Previous Give Up & View Solution 9 Check Answer 0 Next Exit -Explanation / Answer
From the given data
for 79Br and 81Br isotopes
---
Probability of finding two 79Br atoms = a^2
a = 0.5069
so,
Probability of finding two 79Br atoms = (0.5069)^2 x 100 = 25.69%
---
Probability of finding one 79Br and one 81Br atom = 2ab
a = 0.5069
b = 0.4931
so,
Probability of finding one 79Br and one 81Br atom = 2(0.5069 x 0.4931) x 100 = 50%
---
Probability of finding two 81Br atoms = b^2
b = 0.4931
so,
Probability of finding two 81Br atoms = (0.4931)^2 x 100 = 24.31%