Station G: Thermochemistry Part I. Using the data provided below, determine the

Question

Station G: Thermochemistry Part I. Using the data provided below, determine the heat of neutralization for the reaction. Note that the specific heat of water is 4.187 kJ/kg K. Initial temperature of solution of NaOH 28.0°C Initial temperature of solution of HCl 28.0°C Final temperature of solution 42.0 Part II. 2 L of 0.1 M NaOH is mixed with 1 L of 0.2 M HCI. Determine the heat of neutralization per mole of reaction. (Hint: Your final answer should be in kJ/mol.) equation for this neutralization reaction. Part III. Write the net ionic

Explanation / Answer

part 1

   we need amount of solution. to do this

heat liberated(q) = m*S*DT

                   m = mass of the mixture of solution = ?

                   s = specific heatof solution = 4.187 kj/kg.k

                  DT = 42-28 = 14 c

DH0neu = - q/n

n = no of mol of acid(or) base reacted.

part II

no of mol of NaOH = 2*0.1 = 0.2 mol

no of mol of HCl = 1*0.2 = 0.2 mol

NaOH + HCl --> NaCl + H2O

part 3

MOLECULAR equation : NaOH(aq) + HCl(aq) --> NaCl(aq) + H2O(l)

inoic equation : Na^(aq) + OH^-(aq) + H^+(aq)+Cl^-(aq) --> Na^(aq)+Cl^-(aq) + H2O(l)

net inoic equation : OH^-(aq) + H^+(aq) --> H2O(l)

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---