Question (3 points) 1st attempt d See Periodic Table See H The Hsoln of HNO3 is-

Question

Question (3 points) 1st attempt d See Periodic Table See H The Hsoln of HNO3 is-33.3 kumol. 190 mL of 140 M HNO3 is dissolved in 100.0 mL of distilled water initially at 25°C How much ice at 0°C [Cp-37.1 JUmol carts-601 kJ/mol] must be added to return the solution temperature to 25°C after dissolution of the acid and equilibrium with the ice is reached? The molar heat capacity is 80 8 J mol-C) for the solution, and the molar heat capacity is 75.3 mol C) for pure water. g ice 604/o6 o oF 6 qUESTIONS COMPLETED MacBook Air F3 888F 3 4 5 7 WERTYU

Explanation / Answer

no of mol of HNO3 dissolved = 17*13/1000 = 0.221 mol

heat liberated(q) = -33.3*0.221 = -7.36 kj

heat liberated(q) = heat gained by water + HNO3 solution

                  = n*Cm*DT

       7.36*10^3 = (100/18)*75.3*(x-25) + 0.221*80.8+(x-25)

     final temperature of solution = x = 42.51 C

heat gained by ice = heat lost by solution

   (x/18)*37.1*(25-0)+(x/18)*6.01*10^3 = (100/18)*75.3*(42.51-25) + 0.221*80.8+(42.51-25)

x = amount of ice must be added = 19.1 g

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