Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy cha

Question

Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.1, and the temperature is 37.0 °C? G°' for the reaction is –16.7 kJ/mol.

The constant R = 8.3145 J/(mol·K)

nsider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.1, and the temperature is 37.0 °C? for the reaction is-16.7 kJ/mol The constant R = 8.3145 J/(mol K) Number kJ/ mol

Explanation / Answer

it sound like they want us to use the "the ratio of the concentrations of the products to the concentrations of the reactants is 22.1" as the equilibrium constant "K"

if so then use the deltaG = -RTlnK equation,
where R=8.314 J/mol*K

dG = -RTlnK

dG = - (8.314) (310K) (ln 22.1)

dG = - (8.314) (310K) (3.0955)

dG = -7978.35 Joules

dG = - 7.978 kJ

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