Part 2 nce the following redox reactions using the method of hall-reactions and

Question

Part 2 nce the following redox reactions using the method of hall-reactions and clearly show all your ste a, S (s) + NO, (a) so,-(aq) + N,o(g) (in acidic solution) Steps taken to balance first half-reaction Steps taken to balance second half-reaction Complete your work and write the balanced redox reaction below: H2O2 (aq) + ClO2 (aq) CIO, (aq) + O2 (g) (in basic solution) Steps taken to balance first half-reaction Steps taken to balance second half-reaction Complete your work and write the balanced redox reaction below:

Explanation / Answer

a)

S = SO3-2

NO3- = N2O

balace N

S = SO3-2

2NO3- = N2O

balance O

3H2O + S = SO3-2

2NO3- = N2O + 6H2O

balance H

3H2O + S = SO3-2 + 6H+

12H+ + 2NO3- = N2O + 6H2O

balance charge

3H2O + S = SO3-2 + 6H+ + 4e-

10e- + 12H+ + 2NO3- = N2O + 6H2O

balance e-

15H2O + 5S = 5SO3-2 + 30H+ + 20e-

20e- + 24H+ + 2NO3- = 2N2O + 12H2O

add all

20e- + 24H+ + 2NO3- + 15H2O + 5S = 5SO3-2 + 30H+ + 20e- + 2N2O + 12H2O

simplify

2NO3- + 3H2O + 5S = 5SO3-2 + 6H+ + 2N2O

add phases

2NO3-(aq) + 3H2O(l) + 5S(s) = 5SO3-2(aq) + 6H+(aq) + 2N2O (g)

Q2

H2O2= O2

ClO2 = ClO2-

balance H

H2O2= O2 + 2H+

ClO2 = ClO2-

balance charge

H2O2= O2 + 2H+ + 2e-

e- + ClO2 = ClO2-

balance e

H2O2= O2 + 2H+ + 2e-

2e- + 2ClO2 = 2ClO2-

add all

2e- + 2ClO2 + H2O2= O2 + 2H+ + 2e- + 2ClO2-

simlify

2ClO2 + H2O2= O2 + 2H+ + 2ClO2-

add OH-

2OH- + 2ClO2 + H2O2= O2 + 2H2O+ 2ClO2-

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