Analyzing a galvanic cell A galvanic cell is powered by the following redox reac

Question

Analyzing a galvanic cell A galvanic cell is powered by the following redox reaction: 3 Cl2(g) + 2 Mno2(s) + SOH (aq) 6 ci (aa) + 2 MnO4 (aq)-4H2O(1) Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a halanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to 2 decimal places

Explanation / Answer

we know that

reduction takes place at cathode

oxidation takes place at anode

so

balanced equation at cathode :

3 Cl2 (g) + 6e- --> 6 Cl- (aq)

balanced equation at anode :

MnO2 (s) + 4 OH- (aq) --> MnO4- (aq) + 2 H20 (l) + 3e-

now

we know that

Eo cell = Eo cathode - Eo anode

using the standard Eo values for the respective electrodes

Eo cell = 1.36 - (0.595)

Eo cell = 0.765 V

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