Ans - A oxidation number for each element In H2O2 (aq) Oxidation number of H = +
ID: 699521 • Letter: A
Question
Ans - A
oxidation number for each element
In H2O2 (aq)
Oxidation number of H = +1,
O = - 1 ( O is in peroxide form)
In ClO2 (aq)
Cl =+4
O = - 2
In ClO-2 (aq)
Cl = +3
O = - 2
O2 (g) O = 0.
Change in oxidation number
Cl = from 4+ to 3+
O = from -1 to 0.
Cl is reduced
O is oxidized.
Balance the chlorine atoms on both sides
H2O2 (aq) + 2 ClO2 (aq) ---> 2 ClO2- (aq) + O2 (g)
Balance hydrogen atoms by adding OH- ions
H2O2 (aq) + 2 ClO2 (aq) + 2 OH- (aq) ---> 2 ClO2- (aq) + O2 (g) + 2 H2O (l)
balance the charges
Cl2 (g) + 2 OH- (aq) ---> Cl- (aq) + ClO- (aq)
Balance the oxygen atoms by adding H2O
Cl2 (g) + 2 OH- (aq) ---> Cl- (aq) + ClO- (aq) + H2O (l)
Explanation / Answer
Part A
H2O2(aq)+ClO2(aq)ClO2(aq)+O2(g)
Express your answer as a chemical equation. Identify all of the phases in your answer. identify charges and include electrons
PartB
Al(s)+MnO4(aq)MnO2(s)+Al(OH)4(aq)
Express your answer as a chemical equation. Identify all of the phases in your answer. identify charges and include electrons?
Part C