Since there is no information about Temperature and Pressure, it is assumed that
ID: 700182 • Letter: S
Question
Since there is no information about Temperature and Pressure, it is assumed that O2 and He are at STP.
At STP, P = 1 atm , T = 273 K
8) a) It is assumed that O2 gas is at STP
At STP,
P = 1 atm
T = 273 K
Given that Volume of O2 gas V = 56.4 L
number of moles of O2 gas , n = ?
Ideal gas equation is
PV = nRT R = universal gas constant = 0.0821 L.atm/K/mol
n = PV/RT
= 1 atm x 56.4 L / ( 0.0821 L.atm/K/mol x 273 K)
= 2.52 moles
Therefore,
number of moles of O2 in 56.4 L of O2 gas = 2.52 moles
b)
It is assumed that He gas is at STP.
At STP,
P = 1 atm
T = 273 K
Given that number of moles of He gas, n = 0.17 moles
volume of He gas, V = ?
Ideal gas equation is
PV = nRT R = universal gas constant = 0.0821 L.atm/K/mol
V = nRT/P
= 0.17 moles x 0.0821 L.atm/K/mol x 273 K / 1 atm
= 3.81 L
Therefore,
volume occupied by 0.170 mole of He gas = 3.81 L
Explanation / Answer
8]] a) the number of moles of O2 in 56.4 L of O2 gas
b) the volume, in liters, occupied by 0.170 mole of He gas
1.24 If the partial pressures are oxygen 440 torr and helium 40 torr , what is the partial pressure (torr) of the nitrogen in the mixture?
1.25 . If the partial pressure of oxygen drops below 110 mmHg , passengers become drowsy. If this happens, oxygen masks are released. What is the total cabin pressure at which oxygen masks are dropped?