I have no idea how to work out this one problem and got all the components incor
ID: 701622 • Letter: I
Question
I have no idea how to work out this one problem and got all the components incorrect.
Consider this reaction data If you were going to graphically determine the activation energy f this reaction, what points would you plot? products Number Number T (K) k (s 225 0.400 825 0.667 | 225 To avoid rounding errors, use at least three significant figures in all values. point 1: 0400 Number Number oint 2: 825 0.667 Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number 267 600 4.45 × 1 0 What is the activation energy of this reaction? Number - 0.0037 J/ molExplanation / Answer
From Arrhenius equation
ln (k2/k1) = (Ea/R) (1/T1 - 1/T2)
Y = m * X
Point 1
On X-axis
1/T1 = 1/225 = 0.00444 = x1
On Y-axis
ln k1 = ln 0.400 = - 0.91629 = y1
Point 2
On X-axis
1/T2 = 1/825 = 0.001212 = x2
On Y-axis
ln k2 = ln 0.667 = - 0.40496 = y2
Rise = y2-y1 = - 0.40496 + 0.91629 = 0.51133
Run = x2 - x1 = 0.001212 - 0.00444 = 0.003228
Slope = rise/run = 0.51133/(-0.003228) = - 158.404
E/R = 158.404
Activation energy E = 158.404 x 8.314 = 1316.9757 J/mol