Course wome C PS Problem 10.107 C)17 of 17 Part C Assume that an exhaled breath

Question

Course wome C PS Problem 10.107 C)17 of 17 Part C Assume that an exhaled breath of air consists of 74 9 % N2. 15.2 %0. 39 % co,, and 60 % water vapor if the total pressure of the gases is 0 980 atm, calculate the partial pressure of CO2 Express your answer using two significant figures. P 0.04 atm Submit Previosus Answers Request Answer Incorrect, Try Again; 2 attempts remaining Part D Ifthe total pressure of the gases is 0 900 atm calculate the part? prem" Express your answer using two significant igures Type here to search

Explanation / Answer

Part c

Partial pressure of CO2 = mol fraction of CO2 x total pressure

= 0.039 x 0.980

= 0.03822 atm

Part d

Partial pressure of water vapor = mol fraction of water vapor x total pressure

= 0.06 x 0.980

= 0.0588 atm

Part e

Moles of CO2 exhaled = PV/RT

= 0.03822 atm x 0.445 L / 0.0821 L-atm/mol-K x (37+273)

= 6.68 x 10^-4 moles

Part F

combustion of glucose

C6H12O6(s) + 6O2(g) -->6CO2(g) + 6H2O(g)

6 moles of CO2 required = 1 mol of C6H12O6

6.68 x 10^-4 moles of CO2 required = (6.68 x 10^-4/6)

= 1.114 x 10^-4 mol of C6H12O6

Mass of glucose = moles x molecular weight

= 1.114 x 10^-4 mol x 180.156 g/mol

= 0.02 g

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---