Fluid force on vertical plate: Determine the total force on the vertical plate t
ID: 703586 • Letter: F
Question
Fluid force on vertical plate: Determine the total force on the vertical plate that holds back water (forces on plate are in equilibrium, and the plate is stationary) stored at a depth of 45 feet deep, as indicated in the Figure 1 below. Consider that the plate is held in place by pins at the A (top of plate) and B (bottom of plate) positions. The width of the plate (distance into the page) is 200 feet. What is the magnitude of the two forces at the two points A and B? Provide all answers in English units (pounds force or lb). 2. 1.03 atmospheres P A water Farcelete: 20 Plate: 200 ft wide 45 feetExplanation / Answer
Answer:
The magnitude of force due to water at point A is zero.
For magnitude of force at point B:
Area of plate = 200 * 45 ft2 = 9000 ft2
Total Pressure at bottom = Patm + (density of water*g*h)
Patm= 1.03 atm = 2179.703 lbf/ft2
density of water = 62.428 lbf/ft3
g = 32.174 ft/s2
h = 45 ft
Total Pressure at bottom = 92564.834 lbf/ft2
total force at bottom = Total pressure * area of plate = 92564.834 * 200 *45 = 8.33 * 108 lbf