Microsoft Word -Lab 1 xMicrosoft Word - Lab 12 x M thanks hun- bl680@ut x pid-11

Question

Microsoft Word -Lab 1 xMicrosoft Word - Lab 12 x M thanks hun- bl680@ut x pid-11 32475-dt-content-rid-71 57612-1/courses/chem 1023-01-20 18su/Exam%202962 Ke is equal to 255 for the following reaction at 1000 K: CO(8) + Cl2(8) COCl2(g). A reaction mixture at this temperature initially contains the following concentrations: 0.1500 M CO and 0.175 M Cl. Calculate the I following quantities (18 points total) 8. a. (4 points) Calculate reaction quotient (Q) (4 points) The direction (left, right, or no change) that the reaction will shift. b. (10 points) The equilibrium concentrations of CO(g). Cl:(8). and COCI-(8). c.

Explanation / Answer

a) initially there is no COCl2 present in the mixture.so that,

    reaction quotient(Q)

   Q = [COCl2]/[CO][Cl2]

[COCl2] = 0

so that, Q = 0

b) Q<K, So that, forward reaction takes place.

   reaction will shift to right.

c)            CO(g) + Cl2(g) <----> COCl2(g)

    initial 0.15 M   0.175 M         -

    change   -x        -x             +x

    equil   0.15-x    0.175-x          x

   Kc = [COCl2]/[CO][Cl2]

255 =   x/((0.15-x)*(0.175-x))

x = 0.136

at equilbrium,

[COCl2] = x = 0.136 M

[CO] = 0.15-0.136 = 0.014 M

[Cl2] = 0.175-0.136 = 0.039 M

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