Consider the following solvent pairs when mixed: Which are immiscible/miscible?

Question

Consider the following solvent pairs when mixed: Which are immiscible/miscible? If the solvents are immiscible, which solvent would be in the top layer? 1. a. hexane and water b. methylene chloride and water c. ethanol and water d. ether and water Phenols do not exhibit the same pK, values as other alcohols; they are generally more acidic. Using the knowledge that hydrogen acidity is directly related to the stability of the anion formed (the conjugate base), explain why phenol is much more acidic than cyclohexanol. 2. 41

Explanation / Answer

1.(a) Hexane and water are immiscible. Since the density of the hexane is less than that of the water, it will float on top and water will be on bottom.

(b) Methylene chloride and water are immiscible. The density of the Methylene chloride is greater than that of water, so it will be on the bottom and water will be on top.

(c) Ethanol and water are miscible. So they will not form layers.

(d) Ether and water are immiscible. Since the density of ether is less than that of the water, ether will be on the top and water will be on the bottom.

2. Phenol by losing proton forms more resonance stabilized phenoxide ion.if conjugate base is more stable then corresponding acid is more acidic.But cyclo hexanol by losing proton not forms any resonance stabilized conjugate base. So it's corresponding acid is not more acidic.Therefore phenol is more acidic than cyclohexanol.This is also explained in terms of hybridization

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