I need help with the following questions, please answer any you can I am despera
ID: 716263 • Letter: I
Question
I need help with the following questions, please answer any you can I am desperate:
1.) If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, Cl2?
2.) How many grams of H2 are needed to produce 11.88 g of NH3?
3.) How many molecules (not moles) of NH3 are produced from 8.75×104 g of H2?
4.) Detonation of nitroglycerin proceeds as follows: 4C3H5N3O9(l)12CO2(g)+6N2(g)+O2(g)+10H2O(g) many grams of N2 are produced in the detonation?
5.) What mass of carbon dioxide is produced from the complete combustion of 1.20×103 g of methane?
6.)What mass of water is produced from the complete combustion of 1.20×103 g of methane?
Explanation / Answer
1)
Molar mass of Cl2 = 70.9 g/mol
mass of Cl2 = 21 g
mol of Cl2 = (mass)/(molar mass)
= 21/70.9
= 0.2962 mol
Balanced chemical equation is:
2 Al + 3 Cl2 —> 2 AlCl3
According to balanced equation
mol of AlCl3 formed = (2/3)* moles of Cl2
= (2/3)*0.2962
= 0.197 mol
Answer: 0.197 mol
2)
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass of NH3 = 11.88 g
mol of NH3 = (mass)/(molar mass)
= 11.88/17.03
= 0.6974 mol
Balanced chemical equation is:
N2 + 3H2 —> 2 NH3
According to balanced equation
mol of H2 required = (3/2)* moles of NH3
= (3/2)*0.6974
= 1.046 mol
Molar mass of H2 = 2.016 g/mol
mass of H2 = number of mol * molar mass
= 1.046*2.016
= 2.109 g
Answer: 2.11 g
Only 1 question at a time please