Please answer as many questions as you can Thanks 1. For the reaction, N2(g) 3H2
ID: 716451 • Letter: P
Question
Please answer as many questions as you can Thanks 1. For the reaction, N2(g) 3H2(g)2NH3(g). if the rate of formation of ammonia is 0.04 mol/L min, find the rate of disappearance of H2 and N2 during that same time period. 2. For the following reaction, 5Br BrO3 6H3Br2 3H20, the rate of consumption of bromide ion at some time was found to be 0.20 mo/L s. What is the rate of formation of water over the same time period? 3. For the zero-order reaction, 2NH3(g)N2(g) + 3H2(g), k 2.5 x 10 (ar 1 100°C). Determine the reaction rate when, a) NHI 0.020 M, b) [NH3, mo/L min 0.040 M. P, the rate law is rate [AJ[B]. Complete the 4. For the hypothetical reaction, A + 2B [Al. 0.20 following table (assume each trial is carried out at a different temperature). Blo 0.10 0.20 0.12 Trial k(L/mol-s) rate(mol/L.s) 6.0 x 10-6 5.2 x 10-4 1.2 x 10-5 1.2 x 10- 0.45 5. For the reaction, A P, the following rate data were obtained 0.10 0.02 0.09 0.016 0.08 0.013 0.07 0.01 Rate(mol/L s) Write the (differential) rate law for the reaction.Explanation / Answer
1)
rate of reaction = (1/2)*rate of formation of NH3 = (1/3)*rate of disappearance of H2 = rate of disappearance of N2
USE:
(1/3)*rate of disappearance of H2 = (1/2)*rate of formation of NH3
rate of disappearance of H2 = (3/2)*rate of formation of NH3
rate of disappearance of H2 = (3/2)*0.04 mol/L.min
= 0.06 mol/L.min
Use:
rate of disappearance of N2 = (1/2)*rate of formation of NH3
= (1/2)*0.04 mol/L.min
= 0.02 mol/L.min
2)
rate of reaction = (1/5)*rate of consumption of Bromide = (1/3)*rate of formation of H2O
Use:
(1/3)*rate of formation of H2O = (1/5)*rate of consumption of Bromide
rate of formation of H2O = (3/5)*rate of consumption of Bromide
= (3/5)*0.20 mol/L.s
= 0.12 mol/L.s