If the outside of the flask is not dried after the vaporizing the liquid, will t

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If the outside of the flask is not dried after the vaporizing the liquid, will the unknown calculated molecular weight be too high or too low why? Is it too high because the water adds more molecular weight? Assume the atmospheric pressure is 1 ATM but the actual pressure is higher than 1atm. How will this error affect the calculated molar mass of the unknown? I thought it affects the whole result of your answer not sure if there is more too it? If the vapor volume were to be incorrectly recorded as 125 ml, how will this error affect the calculated molar mass of the unknown? I know it does but not sure specifically how If the entire unknown does not vaporize in the 125ml Erlenmeyer flask, will the reported molecular weight. I thought it was less ? Calculate the number of the number of moles of Krypton gas contained in a 5.00 L container at 6.00 ATM and 25 Celsius. If the gas is Argon instead of Krypton, will the answer change?
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Source:ISBN: 0077414438 | Title: Chemistry | Publisher: McGraw-Hill Higher Education

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