Consider the reaction shown below. PbCO3(s) PbO(s) + CO2(g) Calculate the equili
ID: 744735 • Letter: C
Question
Consider the reaction shown below. PbCO3(s) PbO(s) + CO2(g) Calculate the equilibrium pressure of CO2 in the system at the following temperatures. (a) 100Explanation / Answer
consider the following reaction: PbCO3 ->PbO+CO2 and calculate the equilibrium pressure of CO2 in the system at 190C Delta G for CO2 is -394.4 in kj/mol, Delta H kj/mol is -393.5, delta S j/mol*k is 213.6 Delta G for PbCO3 is -625.5, Delta H is -699.1, Delta S is 131.0, Delta G for PbO is -187.9, Delta H is -217.3, Delta S is 68.70 Calculate the Gibbs energy of your reaction Gr(T)= G(PbO)+G(CO2)-G(PbCO3) every G can be calculated from G=H-T*S ; T= 463 K (= 190 C) Now Gr(T) = -R*T*ln Ka -> Ka = a(PbO)* a(CO2)/a(PbCO3), where a is a activity. Activities for solids = 1 -> Ka= a(CO2) is approx. p(CO2) if gas can be considered to be ideal. -> P(CO2)