Aqueous ammonium hydroxide reacts with aqueous cobalt (III) sulfateto produce aq

Question

Aqueous ammonium hydroxide reacts with aqueous cobalt (III) sulfateto produce aqueous ammonium sulfate and sold cobalt (III)hydroxide. When 38.0 g of one of the reactants was fully reactedwith enough of the other reactant, 8.09 g of ammonium sulfate wasobtained, which corresponded to a 25.0% yield.
(a) what type of reaction took place? (b) write the balanced chemical equation? (c) What is the theoretical yield of ammonium sulfate? (d) Which reactant was the limiting reagent?
(a) what type of reaction took place? (b) write the balanced chemical equation? (c) What is the theoretical yield of ammonium sulfate? (d) Which reactant was the limiting reagent?

Explanation / Answer

   b) 6NH4OH (aq) +Co2(SO4)3 -->3(NH4)2SO4 (aq) +2Co(OH)3 (aq)        c) No. of moles of ammonium sulfate produced - 8.09/132.14moles = 0.061 moles    Therefore, theoretical yield = 100/25 x 8.09 gms = 32.36gms    d) No. of moles of each reactant which took part in reaction:       Ammonium hydroxide - 0.061 x 6/3 = 0.122 moles    Cobalt sulfate - 0.061/3 = 0.020 moles    Mass of each reactant :    Ammonium hydroxide - 35 x 0.122 = 4.27 gms       Cobalt sulfate - 0.020 x 155 = 3.1 gms       Therefore, clearly ammonium hydroxide was the limitingreagent

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