A plot of 1/[A] versus time for the hypothetical reaction givenbelow yields a straight line. A B + C If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction? A B + C If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction? If it took 49 sfor the concentration to drop 35 percentfrom its initial value of 0.61 M,what is the rate constant for the reaction?
Explanation / Answer
For first order reactions, the graph of 1/[A] Vstime would be a straight line Formula : ln[A]t = -kt +ln[A]0 ln(0.61*35%) = -k*49s + ln0.61 ln(0.61*35/100) = -k*49s + ln0.61 ln0.2135 = -k*49s + ln0.61 - 1.544 = -k*49s - 0.49 k = 0.0215s-1Hence the rate constant is0.0215s-1 Hence the rate constant is0.0215s-1