Partial Pressure - Calculate the partial pressure of each gas in the container.
ID: 758068 • Letter: P
Question
Partial Pressure - Calculate the partial pressure of each gas in the container.
Here is my work:
moles CH4 = 8 g / 16 g) = 0.5 moles
moles C2H6 = 18 g / 30 g) = 0.6 moles
Total moles:
PV = nRT
n = PV/RT = (5.4 atm) x (10) / (0.0821 * 296K = 2.2234 moles
moles of propane = 2.2234- 0.5 - 0.6 = 1.1234 moles
partial pressure methane = (0.5 / 2.2234) x 5.4 atm = 1.2144 atm
partial pressure ethane = (0.6 / 2.2234) x 5.4 atm = 1.457 atm
partial pressure propane = 2.2234 - .5 - .6 = 1.1234 atm
I enter: "1.21,1.46,2.67" into mastering chemistry and it tells me I am close on methane and ehtane but a little high.
I have not even started B as I can't get A.
Explanation / Answer
Partial pressure= mole fraction* toatal pressure for CH4 Pp= 0.5*5.4/1.1=5*5.4/11=270/11 atm for C2H6 Pp= 0.6*5.4/1.1=6*5.4/11=324/11 atm