Mno4- + SO2----Mn+2 +SO4-2 solve for Basicsolution I get all the way to 5e- +8H

Question

Mno4- + SO2----Mn+2 +SO4-2      solve for Basicsolution I get all the way to 5e- +8H +MnO4-----Mn=2 +4H2O first equation then I amnot sure Mno4- + SO2----Mn+2 +SO4-2      solve for Basicsolution I get all the way to 5e- +8H +MnO4-----Mn=2 +4H2O first equation then I amnot sure

Explanation / Answer

MnO4-   = > Mn2+                   manganese goes from 7+ to 2+ oxidation state, so add 5e- toleft MnO4- + 5e-   =>  Mn2+                  balance O's with OH- (this is basic solution) and H's with H2O MnO4- + 5e- + 4H2O    => Mn2+   + 8OH- SO2   =>  SO42-                         sulfur dioxide has S with +4, and it goes to 6+ in SO42-, so add2e- to right SO2   =>   SO42-  +  2e-             balance O's with OH- (this is basic solution) and H's with H2O SO2 + 4OH- =>  SO42-   +   2e-    +2H2O Multiply MnO4- equation by 2 and the SO2 equation by 5. This getsrid of the electrons 2MnO4- + 10e- + 8H2O    => 2Mn2+   + 16OH-                  5SO2 + 20OH- =>  5SO42-   +   10e-   + 10H2O --------------------------------------------------------- 2MnO4- + 10e- + 8H2O + 5SO2 +20OH-    => 2Mn2+   +16OH- + 5SO42-  +   10e-    + 10H2O eliminate like terms 2MnO4- + 5SO2 + 4OH-   => 2Mn2+ + 5SO42-   +2H2O

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