calculate H for the follow ing reaction: 2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4N

Question

calculate H for the follow ing reaction:                      2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4NH3+3O2----->2N2+6H2O        H = -1531 KJ N2O + H2------->N2+H2O           H = 1367.4KJ H2+1/2O2--->H2O                          H=-285.9KJ calculate H for the follow ing reaction:                      2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4NH3+3O2----->2N2+6H2O        H = -1531 KJ N2O + H2------->N2+H2O           H = 1367.4KJ H2+1/2O2--->H2O                          H=-285.9KJ

Explanation / Answer

              2NH3(g) +3 N2O(g)--->4N2(g) +3H2O(l)                           Hrxn = Hproducts -Hreactants                Hrxn = 3 Hof H2O(l) +4Hof N2(g) - [2Hof NH3(g) +3Hof N2O(g)]                                    Given     H2+1/2O2--->H2O       H=-285.9KJ                     HofH2O = -285.9kJ/mol                 N2O+ H2------->N2+H2O           H = 1367.4KJ                       HofN2O = -1367.4 kJ/mol                     4NH3+3O2----->2N2+6H2O        H = -1531 KJ                     Hof NH3(g) = (1531 /4)kJ/mol                                                = 382.75 kJ/mol              2NH3(g) +3 N2O(g)--->4N2(g) + 3H2O(l)                      Hrxn = [3 (-285.9 kJ/mol) + 4*0] - [2 *382.75kJ/mol + 3*(-1367.4kJ/mol]                                    = -857.7 kJ/mol - 765.5 kJ/mol +4102.2kJ/mol                                    = 2479 kJ/mol                                               HofH2O = -285.9kJ/mol                 N2O+ H2------->N2+H2O           H = 1367.4KJ                       HofN2O = -1367.4 kJ/mol                     4NH3+3O2----->2N2+6H2O        H = -1531 KJ                     Hof NH3(g) = (1531 /4)kJ/mol                                                = 382.75 kJ/mol              2NH3(g) +3 N2O(g)--->4N2(g) + 3H2O(l)                      Hrxn = [3 (-285.9 kJ/mol) + 4*0] - [2 *382.75kJ/mol + 3*(-1367.4kJ/mol]                                    = -857.7 kJ/mol - 765.5 kJ/mol +4102.2kJ/mol                                    = 2479 kJ/mol                            

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