The desorption of a single molecular layer of n-butane from a single crystal of
ID: 768013 • Letter: T
Question
The desorption of a single molecular layer of n-butane from a single crystal of aluminum oxide was found to be first order with a rate constant of 0.128/s at 150 K. a. what is the half-life of the desorption reaction? b. if the surface is initially completely covered with n-butane at 150 K, how long will it take for 25% of the molecules to desorb? For 50% to desorb? c. if the surface is initially completely covered, what fraction will remain covered after 10s? after 20s? I knew how to do a and b. But i have no clue how to do part c?Explanation / Answer
rate = 1300[CH3NC] that means k = 1300 , this is a first order reaction so that means you can use the formula k = .693/ t1/2 meaning t1/2 = half-life